Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 SECTION 2 • This section contains THREE (03)…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 Numeric Response
Published on: August 12, 2026

SECTION 2

• This section contains THREE (03) question stems.

• There are TWO (02) questions corresponding to each question stem.

• The answer to each question is a NUMERICAL VALUE.

• For each question, enter the correct numerical value corresponding to the answer in the designated place using the mouse and the on-screen virtual numeric keypad.

• If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places.

• Answer to each question will be evaluated according to the following marking scheme:

Full Mark : +2 If ONLY the correct numerical value is entered at the designated place;

Zero Marks : 0 In all other cases.

Question Stem for Question Nos. 7 and 8

Question Stem

A Soft plastic bottle, filled with water of density 1 gm/cc, carries an inverted glass test-tube with some air (ideal gas) trapped as shown in the figure. The test-tube has a mass of 5 gm, and it is made of a thick glass of density 2.5 gm/cc. Initially the bottle is sealed at atmospheric pressure p 0 = 10 5 Pa so that the volume of the trapped air is v 0 = 3.3 cc. When the bottle is squeezed from outside at constant temperature, the pressure inside rises and the volume of the trapped air reduces. It is found that the test tube begins to sink at pressure p 0 + p without changing its orientation. At this pressure, the volume of the trapped air is v 0 - v. Let v = X cc and p = Y x 10 3 Pa.

(i) The value of X is_______.

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Text Solution

Verified by Experts
The correct answer is:
0.30

(0.30)

For equilibrium of the test tube

So, (1)

So, v air = 3cc

So, v = 0.3 cc

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